x^2+32x+255=0

Solution for x^2+32x+255=0 equation:

x^2+32x+255=0

a = 1; b = 32; c = +255;
Δ = b2-4ac
Δ = 322-4·1·255
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-2}{2*1}=\frac{-34}{2}
=-17
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+2}{2*1}=\frac{-30}{2}
=-15
$